TAI THAM LETTER LOW KHA·U+1A25

Character Information

Code Point
U+1A25
HEX
1A25
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A8 A5
11100001 10101000 10100101
UTF16 (big Endian)
1A 25
00011010 00100101
UTF16 (little Endian)
25 1A
00100101 00011010
UTF32 (big Endian)
00 00 1A 25
00000000 00000000 00011010 00100101
UTF32 (little Endian)
25 1A 00 00
00100101 00011010 00000000 00000000
HTML Entity
ᨥ
URI Encoded
%E1%A8%A5

Description

U+1A25, or TAI THAM LETTER LOW KHA, is a typographical character from the Unicode Standard, specifically within the "Tai Tham" block. In digital text, it serves as a unique symbol for the lowercase form of the Kha letter in the Tai Tham script, which is used to write various Tai languages such as Sui, Njordin, and Yawan in Southeast Asia. The Tai Tham script was adapted from the ancient Brahmi script, demonstrating the influence of Indian culture on the region's linguistic development. Today, U+1A25 is vital for accurate digital representation and communication in these languages, preserving their cultural heritage in the digital age.

How to type the symbol on Windows

Hold Alt and type 6693 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A25. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A25 to binary: 00011010 00100101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101000 10100101