TAI THAM LETTER LUE·U+1A44

Character Information

Code Point
U+1A44
HEX
1A44
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A9 84
11100001 10101001 10000100
UTF16 (big Endian)
1A 44
00011010 01000100
UTF16 (little Endian)
44 1A
01000100 00011010
UTF32 (big Endian)
00 00 1A 44
00000000 00000000 00011010 01000100
UTF32 (little Endian)
44 1A 00 00
01000100 00011010 00000000 00000000
HTML Entity
ᩄ
URI Encoded
%E1%A9%84

Description

The character U+1A44, TAI THAM LETTER LUE, plays a significant role in the digital representation of the Thai language. It is an essential component of the Thai script, which is part of the larger Tai family of scripts used for various Southeast Asian languages. The TAI THAM LETTER LUE character typically represents the consonant-vowel combination [t] or [d] followed by the vowel [ɯ], and helps to facilitate accurate and efficient communication in Thai digital text. In the context of typography, it is crucial for maintaining the visual integrity and cultural authenticity of Thai text when displayed on digital platforms or printed materials. Its usage ensures that linguistic and cultural nuances are preserved, thereby contributing to the broader goal of promoting cross-cultural understanding and appreciation.

How to type the symbol on Windows

Hold Alt and type 6724 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1A44. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1A44 to binary: 00011010 01000100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101001 10000100