CHARACTER 181D·U+181D

Character Information

Code Point
U+181D
HEX
181D
Unicode Plane
Supplementary Multilingual Plane

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A0 9D
11100001 10100000 10011101
UTF16 (big Endian)
18 1D
00011000 00011101
UTF16 (little Endian)
1D 18
00011101 00011000
UTF32 (big Endian)
00 00 18 1D
00000000 00000000 00011000 00011101
UTF32 (little Endian)
1D 18 00 00
00011101 00011000 00000000 00000000
HTML Entity
᠝
URI Encoded
%E1%A0%9D

Description

The Unicode character U+181D (CHARACTER 181D) holds a significant place in the world of typography and digital text. It represents the Character '☒' or 'CHECKMARK BALLOT', which is commonly used as a tick or cross symbol to denote affirmation, approval or validation. This character is widely used across various software applications, including ballots, forms, surveys, and interactive interfaces where a user needs to confirm an action or select an option. The character's specific design reflects its universal usage across different cultures and languages. It has been meticulously crafted by typography experts to ensure clarity and comprehensibility in digital text.

How to type the symbol on Windows

Hold Alt and type 6173 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+181D. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+181D to binary: 00011000 00011101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100000 10011101