Character Information

Code Point
U+1438
HEX
1438
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 90 B8
11100001 10010000 10111000
UTF16 (big Endian)
14 38
00010100 00111000
UTF16 (little Endian)
38 14
00111000 00010100
UTF32 (big Endian)
00 00 14 38
00000000 00000000 00010100 00111000
UTF32 (little Endian)
38 14 00 00
00111000 00010100 00000000 00000000
HTML Entity
ᐸ
URI Encoded
%E1%90%B8

Description

U+1438 is a Canadian Syllabics character, specifically the "PA" variant. In digital text, this Unicode character plays an important role in representing elements of the Algonquian language family, which includes languages like Ojibwe, Cree, and Inuktitut. These languages are spoken by Indigenous peoples across Canada, particularly in the northern regions. The use of U+1438 helps preserve and promote these diverse linguistic traditions while ensuring accurate digital representation and communication. By accurately depicting phonetic variations in these languages, U+1438 contributes to the richness and understanding of Indigenous cultures and histories within Canada's linguistic landscape.

How to type the symbol on Windows

Hold Alt and type 5176 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1438. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1438 to binary: 00010100 00111000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10010000 10111000