VEDIC SIGN YAJURVEDIC MIDLINE SVARITA·U+1CD4

Character Information

Code Point
U+1CD4
HEX
1CD4
Unicode Plane
Basic Multilingual Plane
Category
Nonspacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B3 94
11100001 10110011 10010100
UTF16 (big Endian)
1C D4
00011100 11010100
UTF16 (little Endian)
D4 1C
11010100 00011100
UTF32 (big Endian)
00 00 1C D4
00000000 00000000 00011100 11010100
UTF32 (little Endian)
D4 1C 00 00
11010100 00011100 00000000 00000000
HTML Entity
᳔
URI Encoded
%E1%B3%94

Description

U+1CD4 is a specialized Unicode character representing the Vedic Sign Yajurvedic Midline Svarita (झ). This character holds importance in digital text as it's used for transcribing Indian languages, particularly those that have roots in the ancient Vedic script. The symbol is crucial in maintaining linguistic accuracy and cultural authenticity when working with these languages. The Vedic Sign Yajurvedic Midline Svarita is a part of the Vedic script system developed during the Vedic period (1500–500 BCE). It's composed of Devanagari, an abugida writing system used for several modern Indo-Aryan languages, and the Brahmi script which was adapted from Aramaic in the 4th century BC. In its cultural context, it's deeply rooted in ancient religious texts like the Rigveda and the Yajurveda of Hinduism. Its technical significance lies in facilitating correct text representation and preserving linguistic integrity in digital communications.

How to type the symbol on Windows

Hold Alt and type 7380 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1CD4. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1CD4 to binary: 00011100 11010100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110011 10010100