BALINESE LETTER HA·U+1B33

Character Information

Code Point
U+1B33
HEX
1B33
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 AC B3
11100001 10101100 10110011
UTF16 (big Endian)
1B 33
00011011 00110011
UTF16 (little Endian)
33 1B
00110011 00011011
UTF32 (big Endian)
00 00 1B 33
00000000 00000000 00011011 00110011
UTF32 (little Endian)
33 1B 00 00
00110011 00011011 00000000 00000000
HTML Entity
ᬳ
URI Encoded
%E1%AC%B3

Description

U+1B33, also known as BALINESE LETTER HA, is a typographical character that plays an essential role in the Balinese language's digital text representation. It belongs to the Unicode Standard, specifically the Supplementary Multilingual Plane (SMP), with the codepoint U+1B33. Balinese, an Austronesian language, has its script based on the Latin alphabet. The BALINESE LETTER HA holds a crucial position in this script system as it represents a significant phoneme in the language's pronunciation and helps preserve the cultural and linguistic heritage of the Balinese people. In digital text processing and encoding, U+1B33 ensures accurate representation of written Balinese language on devices and platforms supporting Unicode, facilitating communication, education, and documentation for the speakers of this language.

How to type the symbol on Windows

Hold Alt and type 6963 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1B33. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1B33 to binary: 00011011 00110011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101100 10110011