BOPOMOFO FINAL LETTER P·U+31B4

Character Information

Code Point
U+31B4
HEX
31B4
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 B4
11100011 10000110 10110100
UTF16 (big Endian)
31 B4
00110001 10110100
UTF16 (little Endian)
B4 31
10110100 00110001
UTF32 (big Endian)
00 00 31 B4
00000000 00000000 00110001 10110100
UTF32 (little Endian)
B4 31 00 00
10110100 00110001 00000000 00000000
HTML Entity
ㆴ
URI Encoded
%E3%86%B4

Description

U+31B4 is a character in the Unicode standard representing Bopomofo Final Letter P (BOPOMOFO FINAL LETTER P). It serves as a significant element within digital text, particularly within the context of the Chinese language and its writing systems. The character holds particular importance in the representation and phonetic transcription of Mandarin Chinese through the use of Bopomofo, which is an auxiliary system that transcribes spoken Mandarin into written form. In this role, U+31B4 contributes to the accurate pronunciation and understanding of Chinese texts by representing a specific sound or syllable when used in conjunction with other Bopomofo characters. Its precise usage and context within digital text are guided by its phonetic function and its position in the Bopomofo system, making it a critical component for those studying or working with Mandarin Chinese.

How to type the symbol on Windows

Hold Alt and type 12724 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31B4. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31B4 to binary: 00110001 10110100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10110100