BOPOMOFO LETTER INNN·U+31B3

Character Information

Code Point
U+31B3
HEX
31B3
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 B3
11100011 10000110 10110011
UTF16 (big Endian)
31 B3
00110001 10110011
UTF16 (little Endian)
B3 31
10110011 00110001
UTF32 (big Endian)
00 00 31 B3
00000000 00000000 00110001 10110011
UTF32 (little Endian)
B3 31 00 00
10110011 00110001 00000000 00000000
HTML Entity
ㆳ
URI Encoded
%E3%86%B3

Description

The Unicode character U+31B3 represents the "BOPOMOFO LETTER INNN" in digital text. This character plays a crucial role in the Bopomofo script, which is used for transcribing the Mandarin Chinese language into a phonetic system. In the context of linguistics and cultural studies, the Bopomofo script has been historically significant as it allows non-native speakers to understand and pronounce Mandarin more accurately. The BOPOMOFO LETTER INNN specifically represents an initial consonant sound followed by a neutral tone. Its usage in digital text contributes to better communication, particularly in linguistic research and teaching of Mandarin Chinese. As part of the Unicode Standard, U+31B3 ensures consistency and accurate representation of characters across different platforms and devices.

How to type the symbol on Windows

Hold Alt and type 12723 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31B3. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31B3 to binary: 00110001 10110011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10110011