BOPOMOFO LETTER AUNN·U+31AF

Character Information

Code Point
U+31AF
HEX
31AF
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 AF
11100011 10000110 10101111
UTF16 (big Endian)
31 AF
00110001 10101111
UTF16 (little Endian)
AF 31
10101111 00110001
UTF32 (big Endian)
00 00 31 AF
00000000 00000000 00110001 10101111
UTF32 (little Endian)
AF 31 00 00
10101111 00110001 00000000 00000000
HTML Entity
ㆯ
URI Encoded
%E3%86%AF

Description

The Bopomofo letter U+31AF plays a significant role in digital text encoding, specifically within the Unicode system. It represents the sound "aun" in Mandarin Chinese and is commonly used in Bopomofo, a phonetic writing system developed for transcribing Mandarin into the Latin alphabet. Bopomofo script is particularly useful for language learners and non-native speakers attempting to pronounce and understand Mandarin's complex tonal structure. In digital communication, U+31AF enables accurate representation of spoken Mandarin sounds, facilitating translation and cross-cultural dialogue. As part of the Unicode system, it ensures consistent encoding across various platforms, contributing to the globalization of information exchange.

How to type the symbol on Windows

Hold Alt and type 12719 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31AF. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31AF to binary: 00110001 10101111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10101111