BOPOMOFO LETTER AINN·U+31AE

Character Information

Code Point
U+31AE
HEX
31AE
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 AE
11100011 10000110 10101110
UTF16 (big Endian)
31 AE
00110001 10101110
UTF16 (little Endian)
AE 31
10101110 00110001
UTF32 (big Endian)
00 00 31 AE
00000000 00000000 00110001 10101110
UTF32 (little Endian)
AE 31 00 00
10101110 00110001 00000000 00000000
HTML Entity
ㆮ
URI Encoded
%E3%86%AE

Description

The Unicode character U+31AE, known as the Bopomofo Letter Ainn, plays a pivotal role in the representation of Mandarin Chinese in digital text. It is part of the Bopomofo script, which simplifies the pronunciation of Chinese characters by representing them with individual symbols that correspond to their sounds. In this case, Bopomofo Letter Ainn (U+31AE) specifically represents the sound "a" or "ai". Despite its seemingly arcane nature, it is crucial in the fields of linguistics, translation, and digital humanities due to China's increasing influence on global communication and commerce. The use of this character helps maintain the integrity of Mandarin pronunciation and meaning across different platforms and devices, making it an essential tool for accurate language representation in the digital age.

How to type the symbol on Windows

Hold Alt and type 12718 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31AE. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31AE to binary: 00110001 10101110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10101110