BOPOMOFO LETTER ENN·U+31A5

Character Information

Code Point
U+31A5
HEX
31A5
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 A5
11100011 10000110 10100101
UTF16 (big Endian)
31 A5
00110001 10100101
UTF16 (little Endian)
A5 31
10100101 00110001
UTF32 (big Endian)
00 00 31 A5
00000000 00000000 00110001 10100101
UTF32 (little Endian)
A5 31 00 00
10100101 00110001 00000000 00000000
HTML Entity
ㆥ
URI Encoded
%E3%86%A5

Description

The Unicode character U+31A5, known as BOPOMOFO LETTER ENN, plays a significant role in the realm of digital text. It is primarily utilized within the Bopomofo system, which serves as a phonetic transcription method for Mandarin Chinese. The Bopomofo script employs this character to represent a specific sound or phoneme. U+31A5 contributes to facilitating accurate pronunciation and phonetic interpretation of Mandarin words, assisting in the learning and teaching of the language. In technical terms, its usage is predominantly found within software programs, dictionaries, and educational resources that cater to Chinese language studies or translations. As such, U+31A5 is an essential component in bridging linguistic gaps between various languages and dialects, promoting cross-cultural communication and understanding.

How to type the symbol on Windows

Hold Alt and type 12709 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31A5. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31A5 to binary: 00110001 10100101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10100101