BOPOMOFO LETTER OO·U+31A6

Character Information

Code Point
U+31A6
HEX
31A6
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 A6
11100011 10000110 10100110
UTF16 (big Endian)
31 A6
00110001 10100110
UTF16 (little Endian)
A6 31
10100110 00110001
UTF32 (big Endian)
00 00 31 A6
00000000 00000000 00110001 10100110
UTF32 (little Endian)
A6 31 00 00
10100110 00110001 00000000 00000000
HTML Entity
ㆦ
URI Encoded
%E3%86%A6

Description

The Unicode character U+31A6, BOPOMOFO LETTER OO, holds a significant role in the Bopomofo script, which is an abugida writing system primarily used for transcribing the Mandarin Chinese language into written form. In digital text, this character typically represents the phoneme /ʊ/ or /o/, depending on its position within a syllable. The character U+31A6 is part of the Bopomofo system that was developed in the early 20th century and is still widely used today for teaching Mandarin Chinese as a foreign language. Its cultural and linguistic context lies in the simplification and standardization of Mandarin pronunciation, which has been beneficial in both language education and the preservation of the Chinese language.

How to type the symbol on Windows

Hold Alt and type 12710 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31A6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31A6 to binary: 00110001 10100110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10100110