BOPOMOFO LETTER IR·U+31A8

Character Information

Code Point
U+31A8
HEX
31A8
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 A8
11100011 10000110 10101000
UTF16 (big Endian)
31 A8
00110001 10101000
UTF16 (little Endian)
A8 31
10101000 00110001
UTF32 (big Endian)
00 00 31 A8
00000000 00000000 00110001 10101000
UTF32 (little Endian)
A8 31 00 00
10101000 00110001 00000000 00000000
HTML Entity
ㆨ
URI Encoded
%E3%86%A8

Description

The character U+31A8 represents the "BOPOMOFO LETTER IR" in Unicode typography. This letter is primarily used in the Bopomofo phonetic alphabet, which is employed for transcribing Mandarin Chinese into a script that can be easily read by speakers of other languages. The Bopomofo system facilitates learning and teaching Mandarin pronunciation through its systematic representation of each syllable's initial consonant, medial consonant, vowel, and final consonant. In digital text, U+31A8 contributes to the accurate transcription and phonetic interpretation of the Mandarin language. This character is crucial in linguistic and technical contexts where precise pronunciation and clear communication are essential, particularly for non-native speakers learning Mandarin or for those using machine translation systems.

How to type the symbol on Windows

Hold Alt and type 12712 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31A8. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31A8 to binary: 00110001 10101000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10101000