BOPOMOFO LETTER ANN·U+31A9

Character Information

Code Point
U+31A9
HEX
31A9
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 A9
11100011 10000110 10101001
UTF16 (big Endian)
31 A9
00110001 10101001
UTF16 (little Endian)
A9 31
10101001 00110001
UTF32 (big Endian)
00 00 31 A9
00000000 00000000 00110001 10101001
UTF32 (little Endian)
A9 31 00 00
10101001 00110001 00000000 00000000
HTML Entity
ㆩ
URI Encoded
%E3%86%A9

Description

The Unicode character U+31A9, known as BOPOMOFO LETTER ANN, is a typographic representation used primarily in digital text. It serves as a crucial component of the Bopomofo script, a phonetic writing system developed by Japanese missionaries in Taiwan for transcribing Mandarin Chinese. The character signifies the sound "an" or "ang," depending on its position within a word or syllable. This phonetic system is essential for language learners and linguists as it facilitates pronunciation practice and transcription of Mandarin tones. Despite being less common in mainstream usage, Bopomofo remains culturally significant in certain linguistic contexts, particularly in Taiwanese education and the study of Chinese languages.

How to type the symbol on Windows

Hold Alt and type 12713 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31A9. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31A9 to binary: 00110001 10101001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10101001