BOPOMOFO LETTER INN·U+31AA

Character Information

Code Point
U+31AA
HEX
31AA
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 AA
11100011 10000110 10101010
UTF16 (big Endian)
31 AA
00110001 10101010
UTF16 (little Endian)
AA 31
10101010 00110001
UTF32 (big Endian)
00 00 31 AA
00000000 00000000 00110001 10101010
UTF32 (little Endian)
AA 31 00 00
10101010 00110001 00000000 00000000
HTML Entity
ㆪ
URI Encoded
%E3%86%AA

Description

The Unicode character U+31AA represents the Bopomofo letter "inn" (彡) in the Bopomofo script, a phonetic writing system used primarily for transcribing Mandarin Chinese into a written form that can be easily pronounced by speakers of other languages. Introduced during the early 20th century, Bopomofo was designed to aid in language learning and communication between speakers with different native languages. The "inn" character specifically represents the initial sound /ɪn/ or /iŋ/, similar to the English sounds "in" and "ing." In digital text, U+31AA is utilized for accurate representation of Mandarin pronunciation, ensuring proper enunciation by non-native speakers and assisting in language learning and translation. Bopomofo script has had significant influence on the development of other phonetic writing systems worldwide, making U+31AA an essential character for facilitating cross-linguistic communication and understanding.

How to type the symbol on Windows

Hold Alt and type 12714 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31AA. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31AA to binary: 00110001 10101010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10101010