BOPOMOFO LETTER UNN·U+31AB

Character Information

Code Point
U+31AB
HEX
31AB
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 AB
11100011 10000110 10101011
UTF16 (big Endian)
31 AB
00110001 10101011
UTF16 (little Endian)
AB 31
10101011 00110001
UTF32 (big Endian)
00 00 31 AB
00000000 00000000 00110001 10101011
UTF32 (little Endian)
AB 31 00 00
10101011 00110001 00000000 00000000
HTML Entity
ㆫ
URI Encoded
%E3%86%AB

Description

U+31AB is the Unicode character code for "BOPOMOFO LETTER UNN," a unique character within the Bopomofo script system used in the Romanization of Mandarin Chinese. In digital text, this character serves as a representation of the initial consonant sound "un," which is utilized to convey specific pronunciation nuances in Mandarin phonetics. The Bopomofo script originated from the Qing Dynasty and was developed to facilitate the learning and teaching of Mandarin Chinese for speakers of other languages, particularly those with no prior exposure to Chinese characters or phonetic systems. It is important to note that U+31AB is not used in traditional or contemporary written Mandarin Chinese; rather, it plays a vital role in linguistic and educational contexts for non-native Mandarin speakers.

How to type the symbol on Windows

Hold Alt and type 12715 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31AB. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31AB to binary: 00110001 10101011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10101011