BOPOMOFO LETTER ZI·U+31A1

Character Information

Code Point
U+31A1
HEX
31A1
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 A1
11100011 10000110 10100001
UTF16 (big Endian)
31 A1
00110001 10100001
UTF16 (little Endian)
A1 31
10100001 00110001
UTF32 (big Endian)
00 00 31 A1
00000000 00000000 00110001 10100001
UTF32 (little Endian)
A1 31 00 00
10100001 00110001 00000000 00000000
HTML Entity
ㆡ
URI Encoded
%E3%86%A1

Description

The Unicode character U+31A1 represents the Bopomofo letter "Zi" (BOPOMOFO LETTER ZI). This character is primarily used in digital text for the purpose of transcribing Mandarin Chinese phonetics, specifically, for pinyin romanization. Pinyin is a standardized orthography system that translates the pronunciation of Chinese characters into the Latin script. Bopomofo is an interim step for those who are not familiar with Chinese characters and helps learners in the process of learning Mandarin. U+31A1 has no special cultural, linguistic, or technical context outside of its role as a phonetic aid in the pinyin system.

How to type the symbol on Windows

Hold Alt and type 12705 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31A1. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31A1 to binary: 00110001 10100001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10100001