BOPOMOFO LETTER JI·U+31A2

Character Information

Code Point
U+31A2
HEX
31A2
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 86 A2
11100011 10000110 10100010
UTF16 (big Endian)
31 A2
00110001 10100010
UTF16 (little Endian)
A2 31
10100010 00110001
UTF32 (big Endian)
00 00 31 A2
00000000 00000000 00110001 10100010
UTF32 (little Endian)
A2 31 00 00
10100010 00110001 00000000 00000000
HTML Entity
ㆢ
URI Encoded
%E3%86%A2

Description

The Unicode character U+31A2, known as the BOPOMOFO LETTER JI, plays a vital role in digital text representing the sounds of the Mandarin Chinese language. This character is predominantly utilized within the Bopomofo phonetic system used for transcribing spoken Chinese into written form. The Bopomofo script, which was developed during the early 20th century, consists of 59 characters and is mainly employed in Taiwan for teaching Mandarin pronunciation. U+31A2, or "BOPOMOFO LETTER JI," specifically represents the initial consonant sound "j" followed by the final vowel sound "i." In this manner, it aids learners and speakers of Mandarin in understanding and articulating phonetic nuances accurately.

How to type the symbol on Windows

Hold Alt and type 12706 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+31A2. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+31A2 to binary: 00110001 10100010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000110 10100010