BOPOMOFO LETTER U·U+3128

Character Information

Code Point
U+3128
HEX
3128
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 84 A8
11100011 10000100 10101000
UTF16 (big Endian)
31 28
00110001 00101000
UTF16 (little Endian)
28 31
00101000 00110001
UTF32 (big Endian)
00 00 31 28
00000000 00000000 00110001 00101000
UTF32 (little Endian)
28 31 00 00
00101000 00110001 00000000 00000000
HTML Entity
ㄨ
URI Encoded
%E3%84%A8

Description

The character U+3128 represents the Bopomofo letter "u" in Unicode, which is a widely used encoding system for representing characters from various languages. This particular character holds significance in digital text, particularly within the context of the Bopomofo phonetic alphabet used in Mandarin Chinese. Bopomofo letters are employed to transcribe pinyin, the official romanization system for Standard Mandarin, and aid in teaching and learning the language. U+3128 specifically represents the sound "u" or "ü" in the Bopomofo system. While it may not have a direct correlation with any specific linguistic culture, its application in digital text allows for accurate transcription and pronunciation guidance for Mandarin Chinese speakers and learners around the world.

How to type the symbol on Windows

Hold Alt and type 12584 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+3128. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+3128 to binary: 00110001 00101000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000100 10101000