BOPOMOFO LETTER I·U+3127

Character Information

Code Point
U+3127
HEX
3127
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 84 A7
11100011 10000100 10100111
UTF16 (big Endian)
31 27
00110001 00100111
UTF16 (little Endian)
27 31
00100111 00110001
UTF32 (big Endian)
00 00 31 27
00000000 00000000 00110001 00100111
UTF32 (little Endian)
27 31 00 00
00100111 00110001 00000000 00000000
HTML Entity
ㄧ
URI Encoded
%E3%84%A7

Description

U+3127, also known as BOPOMOFO LETTER I, is a unique character within the Unicode standard, specifically utilized in digital text. This character holds significant importance due to its role in the Bopomofo phonetic alphabet, which was developed for transcribing Mandarin Chinese into the Latin script. The Bopomofo alphabet is crucial as it serves as an essential tool for non-Chinese speakers to understand and learn Mandarin pronunciation. Each character in the Bopomofo system represents a specific sound or syllable, and U+3127 corresponds to the I sound, often used at the beginning of words. However, despite its importance in linguistic studies and language learning, U+3127 is not commonly found outside of such contexts, as most digital text relies on standard Latin characters for communication.

How to type the symbol on Windows

Hold Alt and type 12583 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+3127. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+3127 to binary: 00110001 00100111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000100 10100111