BOPOMOFO LETTER ZH·U+3113

Character Information

Code Point
U+3113
HEX
3113
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E3 84 93
11100011 10000100 10010011
UTF16 (big Endian)
31 13
00110001 00010011
UTF16 (little Endian)
13 31
00010011 00110001
UTF32 (big Endian)
00 00 31 13
00000000 00000000 00110001 00010011
UTF32 (little Endian)
13 31 00 00
00010011 00110001 00000000 00000000
HTML Entity
ㄓ
URI Encoded
%E3%84%93

Description

The Unicode character U+3113 represents the Bopomofo letter "Zh" (姪), which is used primarily in digital text to transcribe the pronunciation of Mandarin Chinese characters. Bopomofo is a phonetic script developed during the early 20th century in China for transcribing Mandarin, and it plays a crucial role in Chinese language education, particularly in teaching pronunciation to non-native speakers. Each Bopomofo character corresponds to a syllable or sound in Standard Mandarin, facilitating a more systematic approach to learning the language's complex tonal system. The use of U+3113 and other Bopomofo characters has been instrumental in promoting better understanding and communication between Chinese speakers and learners worldwide, contributing significantly to the globalization of the Chinese language.

How to type the symbol on Windows

Hold Alt and type 12563 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+3113. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+3113 to binary: 00110001 00010011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100011 10000100 10010011