LATIN LETTER BIDENTAL PERCUSSIVE·U+02AD

ʭ

Character Information

Code Point
U+02AD
HEX
02AD
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
CA AD
11001010 10101101
UTF16 (big Endian)
02 AD
00000010 10101101
UTF16 (little Endian)
AD 02
10101101 00000010
UTF32 (big Endian)
00 00 02 AD
00000000 00000000 00000010 10101101
UTF32 (little Endian)
AD 02 00 00
10101101 00000010 00000000 00000000
HTML Entity
ʭ
URI Encoded
%CA%AD

Description

The Unicode character U+02AD, known as the Latin Letter Bidental Percussive, is a rarely used letter primarily found in the Old Italic script. In digital text, it serves as a representative of the bidentalis, an ancient type of Roman or Etruscan punch tool used for striking and creating letters on wooden surfaces. Although its usage is limited in modern typography, it holds importance in the study of historical scripts, typographical history, and linguistics. The Latin Letter Bidental Percussive demonstrates the evolution of writing systems and provides insight into ancient techniques employed for creating text.

How to type the ʭ symbol on Windows

Hold Alt and type 0685 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character ʭ has the Unicode code point U+02AD. In UTF-8, it is encoded using 2 bytes because its codepoint is in the range of 0x0080 to 0x07ff.

    Therefore we know that the UTF-8 encoding will be done over 11 bits within the final 16 bits and that it will have the format: 110xxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+02AD to binary: 00000010 10101101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11001010 10101101