LATIN LETTER BILABIAL PERCUSSIVE·U+02AC

ʬ

Character Information

Code Point
U+02AC
HEX
02AC
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
CA AC
11001010 10101100
UTF16 (big Endian)
02 AC
00000010 10101100
UTF16 (little Endian)
AC 02
10101100 00000010
UTF32 (big Endian)
00 00 02 AC
00000000 00000000 00000010 10101100
UTF32 (little Endian)
AC 02 00 00
10101100 00000010 00000000 00000000
HTML Entity
ʬ
URI Encoded
%CA%AC

Description

U+02AC, also known as the Latin Letter Bilabial Percussive, is a typographic character in Unicode that represents the consonant sound found in various languages. This particular symbol is not widely used in everyday digital text due to its limited application in common language scripts. Its primary role lies within linguistic and cultural contexts where it serves as an essential component of specific phonetic systems, such as the one found in the Khoisan language family spoken by indigenous communities in Southern Africa. Despite its relatively obscure presence in digital text, the Latin Letter Bilabial Percussive plays a vital role in accurately representing the unique linguistic characteristics and heritage of these languages, thereby contributing to their preservation and understanding for future generations.

How to type the ʬ symbol on Windows

Hold Alt and type 0684 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character ʬ has the Unicode code point U+02AC. In UTF-8, it is encoded using 2 bytes because its codepoint is in the range of 0x0080 to 0x07ff.

    Therefore we know that the UTF-8 encoding will be done over 11 bits within the final 16 bits and that it will have the format: 110xxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+02AC to binary: 00000010 10101100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11001010 10101100