LIMBU DIGIT TWO·U+1948

Character Information

Code Point
U+1948
HEX
1948
Unicode Plane
Basic Multilingual Plane
Category
Decimal Digit Number

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A5 88
11100001 10100101 10001000
UTF16 (big Endian)
19 48
00011001 01001000
UTF16 (little Endian)
48 19
01001000 00011001
UTF32 (big Endian)
00 00 19 48
00000000 00000000 00011001 01001000
UTF32 (little Endian)
48 19 00 00
01001000 00011001 00000000 00000000
HTML Entity
᥈
URI Encoded
%E1%A5%88

Description

U+1948 is the Unicode code point for LIMBU DIGIT TWO, a character from the Limbu script used in the Limbu language. The Limbu script is primarily used to write the Limbu language, which is spoken by over 300,000 people in the Eastern part of Nepal and the Indian State of Sikkim. Typically found in digital texts, this character represents the numeral two within the Limbu script, serving as a key component for writing numbers in the language. The Limbu script is an abugida system, meaning that it consists of a base consonant with inherent vowels and additional diacritics for modifying those vowels or creating new sounds. As part of the growing digital world, characters like U+1948 play an essential role in preserving and promoting the Limbu language, culture, and heritage by enabling accurate and accessible communication online.

How to type the symbol on Windows

Hold Alt and type 6472 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1948. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1948 to binary: 00011001 01001000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100101 10001000