CONTAINS AS NORMAL SUBGROUP·U+22B3

Character Information

Code Point
U+22B3
HEX
22B3
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8A B3
11100010 10001010 10110011
UTF16 (big Endian)
22 B3
00100010 10110011
UTF16 (little Endian)
B3 22
10110011 00100010
UTF32 (big Endian)
00 00 22 B3
00000000 00000000 00100010 10110011
UTF32 (little Endian)
B3 22 00 00
10110011 00100010 00000000 00000000
HTML Entity
⊳
URI Encoded
%E2%8A%B3

Description

The Unicode character U+22B3, known as "CONTAINS AS NORMAL SUBGROUP," is a symbol primarily used in mathematics and digital text. This typographical symbol is part of the broader set of mathematical symbols defined by the Unicode Standard. Its typical usage is to represent the concept of a normal subgroup within the context of abstract algebra, specifically when dealing with groups in group theory. The character plays a crucial role in mathematical proofs and expressions where the inclusion or containment of elements in various sets or groups are being discussed. Although it may not be widely recognized outside the realm of mathematics and computer science, U+22B3 is an essential tool for professionals working in these fields to accurately convey complex ideas and concepts.

How to type the symbol on Windows

Hold Alt and type 8883 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22B3. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22B3 to binary: 00100010 10110011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001010 10110011