NORMAL SUBGROUP OF·U+22B2

Character Information

Code Point
U+22B2
HEX
22B2
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8A B2
11100010 10001010 10110010
UTF16 (big Endian)
22 B2
00100010 10110010
UTF16 (little Endian)
B2 22
10110010 00100010
UTF32 (big Endian)
00 00 22 B2
00000000 00000000 00100010 10110010
UTF32 (little Endian)
B2 22 00 00
10110010 00100010 00000000 00000000
HTML Entity
⊲
URI Encoded
%E2%8A%B2

Description

The Unicode character U+22B2, known as the "Normal Subgroup of" symbol (ℬ), plays a significant role in digital text, particularly within the realm of algebra and set theory. This mathematical symbol is used to denote a normal subgroup in abstract algebra, specifically when referring to the properties of groups under specific conditions. It highlights the importance of subgroups within a group structure and their connection to the overall group's characteristics. The usage of U+22B2 contributes to precise and accurate communication among mathematicians, researchers, and those studying advanced mathematical concepts. While its application may be niche, the "Normal Subgroup of" symbol holds a vital place in digital text for those working within the realms of algebra, group theory, and related fields.

How to type the symbol on Windows

Hold Alt and type 8882 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22B2. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22B2 to binary: 00100010 10110010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001010 10110010