INTERSECTION·U+2229

Character Information

Code Point
U+2229
HEX
2229
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 88 A9
11100010 10001000 10101001
UTF16 (big Endian)
22 29
00100010 00101001
UTF16 (little Endian)
29 22
00101001 00100010
UTF32 (big Endian)
00 00 22 29
00000000 00000000 00100010 00101001
UTF32 (little Endian)
29 22 00 00
00101001 00100010 00000000 00000000
HTML Entity
∩
URI Encoded
%E2%88%A9

Description

The Unicode character U+2229, also known as the "INTERSECTION" symbol, plays a crucial role in digital text, particularly in mathematical and logical expressions. It is often used to denote the intersection of two or more sets within the context of set theory, indicating that an element belongs to all sets involved. For example, in a Venn diagram, the intersecting area between two circles represents the intersection. This character is vital for accurate communication in various scientific and technical disciplines, as well as in programming languages, where logical operations are commonly represented using symbols instead of textual expressions. Its precise use of space and context-specific meaning ensures clarity and reduces ambiguity in mathematical expressions, making it an essential tool in digital typography.

How to type the symbol on Windows

Hold Alt and type 8745 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2229. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2229 to binary: 00100010 00101001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001000 10101001