Character Information

Code Point
U+2228
HEX
2228
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 88 A8
11100010 10001000 10101000
UTF16 (big Endian)
22 28
00100010 00101000
UTF16 (little Endian)
28 22
00101000 00100010
UTF32 (big Endian)
00 00 22 28
00000000 00000000 00100010 00101000
UTF32 (little Endian)
28 22 00 00
00101000 00100010 00000000 00000000
HTML Entity
∨
URI Encoded
%E2%88%A8

Description

The Unicode character U+2228, also known as the Logical OR symbol (∨), plays a significant role in digital text representation within mathematical expressions and logical operations. As a binary operator, it is typically used to signify the inclusive or operation between two sets or values. In linguistic and cultural contexts, this character is primarily employed in computer science, mathematics, and engineering disciplines. The Logical OR symbol can be found in various programming languages and is an essential element in the development of software applications, algorithms, and logical expressions. Its accurate representation within digital text facilitates effective communication among professionals in these fields, ensuring efficient problem-solving and streamlined design processes.

How to type the symbol on Windows

Hold Alt and type 8744 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2228. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2228 to binary: 00100010 00101000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001000 10101000