Character Information

Code Point
U+2227
HEX
2227
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 88 A7
11100010 10001000 10100111
UTF16 (big Endian)
22 27
00100010 00100111
UTF16 (little Endian)
27 22
00100111 00100010
UTF32 (big Endian)
00 00 22 27
00000000 00000000 00100010 00100111
UTF32 (little Endian)
27 22 00 00
00100111 00100010 00000000 00000000
HTML Entity
∧
URI Encoded
%E2%88%A7

Description

The Unicode character U+2227, also known as the LOGICAL AND symbol, is a mathematical symbol used to represent the logical conjunction operation "AND" in digital text. This symbol is widely employed across various fields such as mathematics, computer science, and engineering, where it helps to express logical relationships between boolean expressions. The LOGICAL AND symbol is distinct from the alphabetic '&' ampersand character, which has a different role and usage within typography. Its use in digital text ensures accuracy and clarity in conveying logical relationships and operations, which are fundamental concepts in computer programming languages and Boolean algebra. The U+2227 LOGICAL AND symbol is integral to the precise representation of these concepts, contributing to the overall understanding and functionality of digital text.

How to type the symbol on Windows

Hold Alt and type 8743 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2227. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2227 to binary: 00100010 00100111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001000 10100111