Character Information

Code Point
U+22BC
HEX
22BC
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8A BC
11100010 10001010 10111100
UTF16 (big Endian)
22 BC
00100010 10111100
UTF16 (little Endian)
BC 22
10111100 00100010
UTF32 (big Endian)
00 00 22 BC
00000000 00000000 00100010 10111100
UTF32 (little Endian)
BC 22 00 00
10111100 00100010 00000000 00000000
HTML Entity
⊼
URI Encoded
%E2%8A%BC

Description

The Unicode character U+22BC represents the logical NAND operation, which is a fundamental concept in computer science and digital text. It is used to describe a binary operation that returns true (or 1) only if both its operands are false (or 0). This character has significant importance in programming languages, digital logic, and various computing applications due to its role in processing information. The NAND symbol is often seen in the context of Boolean algebra, where it plays a critical part in defining computational processes. Its inclusion in Unicode ensures that developers and engineers can communicate complex ideas concisely and accurately using standardized text, thus fostering greater efficiency and clarity within the digital world.

How to type the symbol on Windows

Hold Alt and type 8892 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22BC. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22BC to binary: 00100010 10111100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001010 10111100