Character Information

Code Point
U+22BD
HEX
22BD
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8A BD
11100010 10001010 10111101
UTF16 (big Endian)
22 BD
00100010 10111101
UTF16 (little Endian)
BD 22
10111101 00100010
UTF32 (big Endian)
00 00 22 BD
00000000 00000000 00100010 10111101
UTF32 (little Endian)
BD 22 00 00
10111101 00100010 00000000 00000000
HTML Entity
⊽
URI Encoded
%E2%8A%BD

Description

The Unicode character U+22BD, known as NOR, plays a significant role in digital text as a mathematical symbol representing the logical NOR operation. In this context, NOR stands for "Not OR" and is used to denote the negation of an inclusive or operation between two binary operands. This symbol is particularly essential in Boolean algebra, programming languages, and circuit design, where it helps determine the truth value of compound statements. U+22BD is also utilized in various computer applications that require precise representation of logical operations for efficient functioning. While this character may not be widely recognized by the general public, it holds a crucial position in the technical realm, particularly among engineers, programmers, and digital text specialists.

How to type the symbol on Windows

Hold Alt and type 8893 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22BD. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22BD to binary: 00100010 10111101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001010 10111101