UP RIGHT DIAGONAL ELLIPSIS·U+22F0

Character Information

Code Point
U+22F0
HEX
22F0
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8B B0
11100010 10001011 10110000
UTF16 (big Endian)
22 F0
00100010 11110000
UTF16 (little Endian)
F0 22
11110000 00100010
UTF32 (big Endian)
00 00 22 F0
00000000 00000000 00100010 11110000
UTF32 (little Endian)
F0 22 00 00
11110000 00100010 00000000 00000000
HTML Entity
⋰
URI Encoded
%E2%8B%B0

Description

U+22F0, also known as the Up Right Diagonal Ellipsis, is a typographical character with a unique role in digital text. It represents an arrow that points upwards and to the right, creating an optical illusion of movement or progression when used in sequences. The typical usage of this character is to show an arrow in mathematical expressions or diagrams, where it can represent the derivative of a function or denote a change in a specific direction. This character has applications in various fields such as mathematics, computer programming, and technical writing. Its use can be seen across numerous documents, including textbooks, programming languages like LaTeX, and online forums focused on mathematics and computer science. The Unicode character U+22F0 plays a significant role in conveying the concept of motion or change in direction clearly and concisely, making it an essential tool in digital text communication.

How to type the symbol on Windows

Hold Alt and type 8944 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22F0. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22F0 to binary: 00100010 11110000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001011 10110000