APL FUNCTIONAL SYMBOL DEL DIAERESIS·U+2362

Character Information

Code Point
U+2362
HEX
2362
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8D A2
11100010 10001101 10100010
UTF16 (big Endian)
23 62
00100011 01100010
UTF16 (little Endian)
62 23
01100010 00100011
UTF32 (big Endian)
00 00 23 62
00000000 00000000 00100011 01100010
UTF32 (little Endian)
62 23 00 00
01100010 00100011 00000000 00000000
HTML Entity
⍢
URI Encoded
%E2%8D%A2

Description

The Unicode character U+2362, known as APL FUNCTIONAL SYMBOL DEL DIAERESIS, plays a significant role in digital text by serving as a functional symbol in the field of applied mathematics and computing. It is predominantly used in the APL programming language to represent specific functions or operations. APL, which stands for A Programming Language, was developed by Charles Wheelwright in 1962. The language has a unique feature where it allows its users to perform mathematical calculations through a functional notation system, eliminating the need for parentheses and making it more concise. U+2362 is an essential character within this notation system, as it assists in defining the specific operation or function that is intended to be performed.

How to type the symbol on Windows

Hold Alt and type 9058 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2362. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2362 to binary: 00100011 01100010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001101 10100010