APL FUNCTIONAL SYMBOL UP TACK DIAERESIS·U+2361

Character Information

Code Point
U+2361
HEX
2361
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8D A1
11100010 10001101 10100001
UTF16 (big Endian)
23 61
00100011 01100001
UTF16 (little Endian)
61 23
01100001 00100011
UTF32 (big Endian)
00 00 23 61
00000000 00000000 00100011 01100001
UTF32 (little Endian)
61 23 00 00
01100001 00100011 00000000 00000000
HTML Entity
⍡
URI Encoded
%E2%8D%A1

Description

The Unicode character U+2361, known as the APL Functional Symbol Up Tack Diaeresis, is a typographical symbol used primarily in digital text, specifically within the context of the APL programming language and mathematical notation. This particular symbol serves a unique role in that it combines two distinct features: an "up tack" (a small upward-pointing arrow), which indicates an operation or function, and a diaeresis (¨), which modifies the sound or structure of a base character. While the APL Functional Symbol Up Tack Diaeresis may not be widely recognized in mainstream typography, it remains essential within niche domains such as computer science and advanced mathematics, where its specialized functions are indispensable for clear communication of complex ideas.

How to type the symbol on Windows

Hold Alt and type 9057 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2361. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2361 to binary: 00100011 01100001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001101 10100001