APL FUNCTIONAL SYMBOL QUAD COLON·U+2360

Character Information

Code Point
U+2360
HEX
2360
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8D A0
11100010 10001101 10100000
UTF16 (big Endian)
23 60
00100011 01100000
UTF16 (little Endian)
60 23
01100000 00100011
UTF32 (big Endian)
00 00 23 60
00000000 00000000 00100011 01100000
UTF32 (little Endian)
60 23 00 00
01100000 00100011 00000000 00000000
HTML Entity
⍠
URI Encoded
%E2%8D%A0

Description

The character U+2360, also known as APL FUNCTIONAL SYMBOL QUAD COLON, is a typographical symbol primarily used in the field of digital text, particularly within programming languages and mathematical expressions. It originated from the Algebraic Notation System introduced by the American computer scientist Alonzo Church. Its typical usage involves representing the concept of "quadruple application" or "four-fold repetition," which is a fundamental operation in APL programming language. As an esoteric character, U+2360 doesn't have any notable cultural, linguistic, or technical context outside of its niche usage in APL and similar algebraic notation systems. However, it plays a crucial role in these specific applications due to its efficient representation of complex operations with concise notation.

How to type the symbol on Windows

Hold Alt and type 9056 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2360. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2360 to binary: 00100011 01100000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001101 10100000