ERASE TO THE LEFT·U+232B

Character Information

Code Point
U+232B
HEX
232B
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8C AB
11100010 10001100 10101011
UTF16 (big Endian)
23 2B
00100011 00101011
UTF16 (little Endian)
2B 23
00101011 00100011
UTF32 (big Endian)
00 00 23 2B
00000000 00000000 00100011 00101011
UTF32 (little Endian)
2B 23 00 00
00101011 00100011 00000000 00000000
HTML Entity
⌫
URI Encoded
%E2%8C%AB

Description

The Unicode character U+232B, commonly referred to as the "ERASE TO THE LEFT" symbol, plays a significant role in digital text by facilitating editing processes. This typographical character is primarily used in word processors and other text-editing software applications for users to easily correct or revise their work. It allows for the swift deletion of the text preceding it when clicked or selected. While this symbol might not have a direct cultural, linguistic, or technical context, it does contribute to the efficiency and accuracy of digital communication and documentation. Its usage is particularly prominent in programming languages and coding environments where precision is crucial. The "ERASE TO THE LEFT" symbol has become an essential tool for users worldwide, streamlining the editing process across various platforms and applications.

How to type the symbol on Windows

Hold Alt and type 9003 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+232B. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+232B to binary: 00100011 00101011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001100 10101011