RIGHT-POINTING ANGLE BRACKET·U+232A

Character Information

Code Point
U+232A
HEX
232A
Unicode Plane
Basic Multilingual Plane
Category
Close Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8C AA
11100010 10001100 10101010
UTF16 (big Endian)
23 2A
00100011 00101010
UTF16 (little Endian)
2A 23
00101010 00100011
UTF32 (big Endian)
00 00 23 2A
00000000 00000000 00100011 00101010
UTF32 (little Endian)
2A 23 00 00
00101010 00100011 00000000 00000000
HTML Entity
⟩
URI Encoded
%E2%8C%AA

Description

The Unicode character U+232A, known as the Right-Pointing Angle Bracket, is a mathematical symbol used to denote the inequality between two mathematical expressions. In digital text, it plays a crucial role in representing mathematical concepts, particularly in the field of algebra and calculus. This symbol is often employed within the context of mathematical notation systems like LaTeX and MathML, which are widely utilized for presenting mathematical equations accurately on digital platforms. The Right-Pointing Angle Bracket symbol is an indispensable tool for mathematicians, scientists, and engineers who rely on precise and unambiguous communication in their respective fields. Despite its technical nature, this character does not hold any specific cultural or linguistic significance beyond its mathematical application.

How to type the symbol on Windows

Hold Alt and type 9002 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+232A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+232A to binary: 00100011 00101010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001100 10101010