METRICAL LONG OVER SHORT·U+23D2

Character Information

Code Point
U+23D2
HEX
23D2
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8F 92
11100010 10001111 10010010
UTF16 (big Endian)
23 D2
00100011 11010010
UTF16 (little Endian)
D2 23
11010010 00100011
UTF32 (big Endian)
00 00 23 D2
00000000 00000000 00100011 11010010
UTF32 (little Endian)
D2 23 00 00
11010010 00100011 00000000 00000000
HTML Entity
⏒
URI Encoded
%E2%8F%92

Description

The Unicode character U+23D2, also known as the Metrical Long Over Short (MLOS), plays a crucial role in music notation and transcription, particularly in the representation of rhythmic values. Its typical usage is to denote a relationship between two adjacent notes or rests, where one is twice as long as the other. This character helps musicians and composers accurately transcribe complex rhythms and understand the underlying metrical structure of a piece of music. Although not widely used in digital text outside of specialized musical contexts, its inclusion in the Unicode standard ensures that it can be reliably displayed and processed by modern software applications.

How to type the symbol on Windows

Hold Alt and type 9170 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23D2. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23D2 to binary: 00100011 11010010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001111 10010010