METRICAL SHORT OVER LONG·U+23D3

Character Information

Code Point
U+23D3
HEX
23D3
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8F 93
11100010 10001111 10010011
UTF16 (big Endian)
23 D3
00100011 11010011
UTF16 (little Endian)
D3 23
11010011 00100011
UTF32 (big Endian)
00 00 23 D3
00000000 00000000 00100011 11010011
UTF32 (little Endian)
D3 23 00 00
11010011 00100011 00000000 00000000
HTML Entity
⏓
URI Encoded
%E2%8F%93

Description

The Unicode character U+23D3, known as the Metrical Short Over Long (MSOL), plays a vital role in music notation within digital text. Its primary function is to indicate the relationship between short and long notes in rhythmic patterns. Specifically, it signifies that the following note should be treated as a short note, while maintaining its inherent duration or pitch value. The MSOL character can be found in various digital music notation software and formats, including MusicXML and LilyPond. In these contexts, accurate usage of the MSOL character is crucial for conveying correct rhythmic structures and ensuring proper interpretation by musicians and music software alike. Overall, U+23D3 serves as a valuable tool in enabling precise musical expression within digital environments.

How to type the symbol on Windows

Hold Alt and type 9171 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23D3. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23D3 to binary: 00100011 11010011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001111 10010011