METRICAL LONG OVER TWO SHORTS·U+23D4

Character Information

Code Point
U+23D4
HEX
23D4
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8F 94
11100010 10001111 10010100
UTF16 (big Endian)
23 D4
00100011 11010100
UTF16 (little Endian)
D4 23
11010100 00100011
UTF32 (big Endian)
00 00 23 D4
00000000 00000000 00100011 11010100
UTF32 (little Endian)
D4 23 00 00
11010100 00100011 00000000 00000000
HTML Entity
⏔
URI Encoded
%E2%8F%94

Description

The Unicode character U+23D4, known as the Metrical Long Over Two Shorts (MLEO), is a typographic symbol primarily used in digital text for musical notation. In this context, it represents a metrical structure where two shorter notes or rests precede a longer note, often used to emphasize rhythmic patterns or accents within a composition. This character contributes to the precise representation of musical ideas in sheet music and other forms of digital notation, enhancing the readability and clarity for musicians and composers. While its usage may be relatively niche, it plays an important role in ensuring accurate interpretation and performance of musical works across different platforms and devices.

How to type the symbol on Windows

Hold Alt and type 9172 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23D4. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23D4 to binary: 00100011 11010100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001111 10010100