NEW TAI LUE LETTER HIGH NGA·U+1984

Character Information

Code Point
U+1984
HEX
1984
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A6 84
11100001 10100110 10000100
UTF16 (big Endian)
19 84
00011001 10000100
UTF16 (little Endian)
84 19
10000100 00011001
UTF32 (big Endian)
00 00 19 84
00000000 00000000 00011001 10000100
UTF32 (little Endian)
84 19 00 00
10000100 00011001 00000000 00000000
HTML Entity
ᦄ
URI Encoded
%E1%A6%84

Description

The Unicode character U+1984 represents "NEW TAI LUE LETTER HIGH NGA" in the New Tai Lue script, a writing system primarily used for the Tai Lue language spoken by various ethnic groups in Southeast Asia. This particular character is part of the Unicode Standard, which aims to provide a unique code point for every character, symbol, or emoji that can be used in digital text. In its role within the New Tai Lue script, U+1984 serves as the high-tone counterpart to the letter "nGA," helping convey distinct grammatical, semantic, and tonal nuances essential for proper communication in the Tai Lue language. As a typographical expert, it is important to recognize that characters like U+1984 contribute to the richness and diversity of written expression across different languages and cultures around the world.

How to type the symbol on Windows

Hold Alt and type 6532 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1984. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1984 to binary: 00011001 10000100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100110 10000100