NEW TAI LUE LETTER HIGH XA·U+1983

Character Information

Code Point
U+1983
HEX
1983
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A6 83
11100001 10100110 10000011
UTF16 (big Endian)
19 83
00011001 10000011
UTF16 (little Endian)
83 19
10000011 00011001
UTF32 (big Endian)
00 00 19 83
00000000 00000000 00011001 10000011
UTF32 (little Endian)
83 19 00 00
10000011 00011001 00000000 00000000
HTML Entity
ᦃ
URI Encoded
%E1%A6%83

Description

U+1983, also known as NEW TAI LUE LETTER HIGH XA, is a specialized typographic character primarily used in digital text within the New Tai Lue language. It plays a crucial role in the accurate representation of this indigenous Southeast Asian language, which belongs to the Kra-Dai language family and is predominantly spoken by the Tai Lue people in countries such as China, Laos, and Thailand. The character's usage helps maintain the linguistic integrity and cultural identity of the speakers. Although not widely known or used outside of its specific context, U+1983 contributes significantly to the legibility and comprehension of texts within the New Tai Lue community. Its accurate representation is vital in preserving and promoting this lesser-known language for future generations.

How to type the symbol on Windows

Hold Alt and type 6531 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1983. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1983 to binary: 00011001 10000011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100110 10000011