NEW TAI LUE LETTER HIGH QA·U+1980

Character Information

Code Point
U+1980
HEX
1980
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A6 80
11100001 10100110 10000000
UTF16 (big Endian)
19 80
00011001 10000000
UTF16 (little Endian)
80 19
10000000 00011001
UTF32 (big Endian)
00 00 19 80
00000000 00000000 00011001 10000000
UTF32 (little Endian)
80 19 00 00
10000000 00011001 00000000 00000000
HTML Entity
ᦀ
URI Encoded
%E1%A6%80

Description

U+1980 (NEW TAI LUE LETTER HIGH QA) is a typographical character from the Unicode Standard, which encompasses a vast range of characters used in digital text across multiple languages and scripts worldwide. This particular character is specific to the New Tai Lue language, spoken by the Tai Lue ethnic group in Southeast Asia, primarily in Laos. In its typical usage within digital texts, U+1980 (NEW TAI LUE LETTER HIGH QA) serves as a key element in representing and encoding the phonetic and syntactic structures of the New Tai Lue language, allowing for accurate communication and information exchange among speakers of this unique linguistic community. As with many Unicode characters, U+1980 (NEW TAI LUE LETTER HIGH QA) plays a crucial role in preserving the cultural identity and linguistic heritage of its users, fostering both oral and written literacy within this distinct group.

How to type the symbol on Windows

Hold Alt and type 6528 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1980. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1980 to binary: 00011001 10000000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100110 10000000