NEW TAI LUE LETTER LOW QA·U+1981

Character Information

Code Point
U+1981
HEX
1981
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A6 81
11100001 10100110 10000001
UTF16 (big Endian)
19 81
00011001 10000001
UTF16 (little Endian)
81 19
10000001 00011001
UTF32 (big Endian)
00 00 19 81
00000000 00000000 00011001 10000001
UTF32 (little Endian)
81 19 00 00
10000001 00011001 00000000 00000000
HTML Entity
ᦁ
URI Encoded
%E1%A6%81

Description

The Unicode character U+1981, known as NEW TAI LUE LETTER LOW QA, plays a significant role in digital text by representing a specific sound or phoneme in the Tai Lue language, which is spoken primarily in the northern regions of Thailand and Myanmar. It belongs to the writing system of the Tai-Kadai family, which includes several languages like Thai, Lao, and Karen. The character's cultural and linguistic importance lies in its contribution to the representation of the unique sound or phoneme it represents, enabling accurate communication and preservation of the Tai Lue language in digital contexts. In typography, U+1981 adheres to Unicode's specifications, ensuring consistent rendering across different platforms and devices, promoting linguistic diversity and accessibility in the digital world.

How to type the symbol on Windows

Hold Alt and type 6529 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1981. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1981 to binary: 00011001 10000001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100110 10000001