LATIN SMALL LETTER EZH WITH RETROFLEX HOOK·U+1D9A

Character Information

Code Point
U+1D9A
HEX
1D9A
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 9A
11100001 10110110 10011010
UTF16 (big Endian)
1D 9A
00011101 10011010
UTF16 (little Endian)
9A 1D
10011010 00011101
UTF32 (big Endian)
00 00 1D 9A
00000000 00000000 00011101 10011010
UTF32 (little Endian)
9A 1D 00 00
10011010 00011101 00000000 00000000
HTML Entity
ᶚ
URI Encoded
%E1%B6%9A

Description

The Unicode character U+1D9A, known as "LATIN SMALL LETTER EZH WITH RETROFLEX HOOK", is a specialized letter that plays a significant role in digital text representing certain languages. In typography and linguistics, it serves to denote the sound 'ɛ' or 'ɛː', which is an open-mid back unrounded vowel in phonetics. This character is primarily used within the Gurmukhi script, a writing system predominantly employed for writing the Punjabi language. It has a retroflex hook, an indication of its position in the alphabet and a symbol that helps with pronunciation. The use of this character contributes to the richness and diversity of written communication across various cultures and languages.

How to type the symbol on Windows

Hold Alt and type 7578 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D9A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D9A to binary: 00011101 10011010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10011010