MODIFIER LETTER SMALL TURNED ALPHA·U+1D9B

Character Information

Code Point
U+1D9B
HEX
1D9B
Unicode Plane
Basic Multilingual Plane
Category
Modifier Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 9B
11100001 10110110 10011011
UTF16 (big Endian)
1D 9B
00011101 10011011
UTF16 (little Endian)
9B 1D
10011011 00011101
UTF32 (big Endian)
00 00 1D 9B
00000000 00000000 00011101 10011011
UTF32 (little Endian)
9B 1D 00 00
10011011 00011101 00000000 00000000
HTML Entity
ᶛ
URI Encoded
%E1%B6%9B

Description

The Unicode character U+1D9B, known as the Modifier Letter Small Turned Alpha, plays a significant role in digital typography, specifically in creating diacritic marks for various alphabets. This character is commonly used to represent the "turned small" form of uppercase Latin letters, which involves rotating the letter by 90 degrees clockwise while maintaining its orientation relative to the base line. In linguistic and cultural contexts, this character has been widely adopted in various languages that employ modified alphabets, such as Icelandic, where it is used alongside the "Turned A" character (U+1D9C) for consistency in typography. By adhering to strict accuracy and precision, U+1D9B contributes to the accurate representation of language-specific features and helps preserve linguistic identity and heritage in digital texts.

How to type the symbol on Windows

Hold Alt and type 7579 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D9B. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D9B to binary: 00011101 10011011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10011011