LATIN SMALL LETTER G WITH PALATAL HOOK·U+1D83

Character Information

Code Point
U+1D83
HEX
1D83
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 83
11100001 10110110 10000011
UTF16 (big Endian)
1D 83
00011101 10000011
UTF16 (little Endian)
83 1D
10000011 00011101
UTF32 (big Endian)
00 00 1D 83
00000000 00000000 00011101 10000011
UTF32 (little Endian)
83 1D 00 00
10000011 00011101 00000000 00000000
HTML Entity
ᶃ
URI Encoded
%E1%B6%83

Description

U+1D83, the Latin Small Letter G with Palatal Hook, is a unique Unicode character that plays a crucial role in typography and digital text representation. This particular glyph is derived from the Spanish alphabet and is used to represent the palatal "g" sound in certain dialects of Spanish, specifically those spoken in Central America and parts of South America. It is a vital component for accurate transcription and translation of these regional dialects in digital communication, literature, and educational materials. The character is not commonly used outside its specific linguistic context, but its inclusion in Unicode (as part of the Latin Extended-C set) ensures that it remains accessible to typographers and digital content creators who need to represent this distinct sound accurately.

How to type the symbol on Windows

Hold Alt and type 7555 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D83. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D83 to binary: 00011101 10000011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10000011