LATIN SMALL LETTER K WITH PALATAL HOOK·U+1D84

Character Information

Code Point
U+1D84
HEX
1D84
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 84
11100001 10110110 10000100
UTF16 (big Endian)
1D 84
00011101 10000100
UTF16 (little Endian)
84 1D
10000100 00011101
UTF32 (big Endian)
00 00 1D 84
00000000 00000000 00011101 10000100
UTF32 (little Endian)
84 1D 00 00
10000100 00011101 00000000 00000000
HTML Entity
ᶄ
URI Encoded
%E1%B6%84

Description

The Unicode character U+1D84, known as the Latin Small Letter K with Palatal Hook (Ḃ), serves a specific role in digital text by representing a unique variation of the lowercase letter "k." Its design features a palatal hook, which is an upward curve at the left side of the letter. This character primarily finds usage in typographical contexts, particularly for demonstrating various alphabetic scripts or showcasing special letters in typesetting projects. Although it may not have a direct application within spoken languages, U+1D84 can be used to convey certain phonetic distinctions or represent specific dialectal features in written text. Its use in linguistic studies and cultural preservation efforts highlights the importance of preserving diverse writing systems and maintaining a comprehensive character set for accurate digital representation.

How to type the symbol on Windows

Hold Alt and type 7556 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D84. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D84 to binary: 00011101 10000100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10000100