LATIN SMALL LETTER L WITH PALATAL HOOK·U+1D85

Character Information

Code Point
U+1D85
HEX
1D85
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 85
11100001 10110110 10000101
UTF16 (big Endian)
1D 85
00011101 10000101
UTF16 (little Endian)
85 1D
10000101 00011101
UTF32 (big Endian)
00 00 1D 85
00000000 00000000 00011101 10000101
UTF32 (little Endian)
85 1D 00 00
10000101 00011101 00000000 00000000
HTML Entity
ᶅ
URI Encoded
%E1%B6%85

Description

The Unicode character U+1D85 represents the "Latin Small Letter L with Palatal Hook" (Ḽ). It is a less commonly used letter in the Latin script that primarily finds its application in linguistic and typographic contexts. Its usage is typically found in specialized digital text environments, such as constructed languages or typographical experiments. The character gets its name from the distinct palatal hook present at the bottom of the letter 'L'. While it does not have a direct representation in any major world language, it holds significance for linguists and typographers who appreciate the nuance and variation within the Latin script. In terms of technical context, the Unicode character U+1D85 is encoded in the "Latin Extended-C" block (U+1D80-U+1DBF) which contains additional letters that extend the standard Latin alphabet to accommodate various languages and scripts.

How to type the symbol on Windows

Hold Alt and type 7557 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D85. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D85 to binary: 00011101 10000101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10000101