SUNDANESE LETTER A·U+1B83

Character Information

Code Point
U+1B83
HEX
1B83
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 AE 83
11100001 10101110 10000011
UTF16 (big Endian)
1B 83
00011011 10000011
UTF16 (little Endian)
83 1B
10000011 00011011
UTF32 (big Endian)
00 00 1B 83
00000000 00000000 00011011 10000011
UTF32 (little Endian)
83 1B 00 00
10000011 00011011 00000000 00000000
HTML Entity
ᮃ
URI Encoded
%E1%AE%83

Description

The Unicode character U+1B83, known as the Sundanese Letter A, is a significant element in the Sundanese script, which represents the Indonesian language of Sunda. In digital text, this character plays a critical role in preserving and transmitting the linguistic heritage of the Sundanese people, enabling accurate communication among its speakers. The Sundanese script, which includes the U+1B83 character, is an essential component of the rich cultural and linguistic history of West Java, Indonesia. This character's presence on digital platforms helps maintain and propagate this unique writing system and associated culture while adhering to international Unicode standards for accurate and efficient text encoding.

How to type the symbol on Windows

Hold Alt and type 7043 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1B83. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1B83 to binary: 00011011 10000011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10101110 10000011